(8x^3+2x^2-72)/(1x-2)

Solution for (8x^3+2x^2-72)/(1x-2) equation:

D( x )

1*x-2 = 0

1*x-2 = 0

1*x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(8*x^3+2*x^2-72)/(1*x-2) = 0

(8*x^3+2*x^2-72)/(x-2) = 0

8*x^3+2*x^2-72 = 0

2*(4*x^3+x^2-36) = 0

4*x^3+x^2-36 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 9, -9, 12, -12, 18, -18, 36, -36 }

1

x = 1

4*x^3+x^2-36 = -31

1

-1

x = -1

4*x^3+x^2-36 = -39

-1

2

x = 2

4*x^3+x^2-36 = 0

2

x-2

4*x^2+9*x+18

4*x^3+x^2-36

x-2

8*x^2-4*x^3

9*x^2-36

18*x-9*x^2

18*x-36

36-18*x

0

4*x^2+9*x+18 = 0

DELTA = 9^2-(4*4*18)

DELTA = -207

DELTA < 0

x in { 2} 

2*(x-2) = 0

2 = 0

x belongs to the empty set